本次数据库代写是限时完成数据库测试题
FIT9132
SAMPLE EXAM PAPER
Q1. Relational Model (6 + 1 + 3 = 10 marks)
A company wishes to record the following attributes about their employees: employee ID,
department number, name, home address, education qualifications and skills which the
employee has.
A small sample of data is show below:
Employee
ID
Department
Number
Employee
Name
Home
Address
Qualification Skill
101 21 Given name:
Joe
Family name:
Bloggs
Street: 12
Wide Rd
Town: Mytown
Postcode:
1234
Bachelor of
Commerce
MBA
Project
Management
Hadoop
R
102 13 Given name:
Wendy
Family name:
Xiu
Street: 55
Narrow St
Town: Mytown
Postcode:
1234
Bachelor of
Computer
Science
Master of IT
Doctor of
Philosophy
SQL
PL/SQL
103 13 Given name:
Sarah
Family name:
Green
Street: 25
High St Rd
Town: Mytown
Postcode:
1234
Certificate IV in
Business
Administration
SQL
Java
Phyton
(a) Use this data to explain the difference between a simple attribute, a composite
attribute and a multivalued attribute. Your answer must include examples drawn from
this data.
[6 marks]
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(b) The following relations represent a publications database.
Authors write papers which are published in an edition of a journal.
Each edition of a journal is assigned a journal id and appoints an editor.
A given paper may be authored by several authors, in such cases each author is assigned
a position representing their contribution to the paper:
author (author_id, first_name, last_name)
author_paper (author_id, paper_id, author_position)
paper (paper_id, paper_title, journal_id)
journal (journal_id, journal_title, month, year, editor)
● Primary keys are underlined
● editor in journal references author(author_id) – this is an author acting as the
journal editor
Write the relational algebra for the following queries (your answer must show an
understanding of query efficiency):
(i) Show all the journal titles.
[1 mark]
(ii) Show the paper title, journal title and month and year of publication for all papers
published before 2012
[3 marks]
Page 3 of 13
Q2 Database Design (20 marks)
Monash Computing Students Society (MCSS) is one of the student clubs at Monash
University.
Students are welcome to join as a member. When a student joins MCSS, a member id is
assigned, and the students first name, last name, date of birth, email and phone number
will be recorded. This club has an annual membership fee. When a member has paid
the membership fee for the current year, the current year is recorded against the year of
membership as part of their membership details.
MCSS hosts several events throughout the year. The events are currently categorised
into Professional Events, General Events, and Social Events. MCSS would like to be
able to add further categories as they develop new events, When an event is scheduled,
MCSS assigns an event id to the event. The event date and time, description, location,
allocated budget, the ticket price and the discount rate (eg 5%) for members. Some
events are organised as free events for members. In this situation, the discount rate is
recorded as 100% for members. For all events, only members can purchase the tickets.
However, members can buy additional tickets for their friends or family at full price. For
each of the sales, the receipt number, number of tickets sold, total amount paid and the
member id are recorded.
Some events attract some sponsorships. The sponsor may be an organisation or an
individual. The sponsors provide financial support to the event. Some events may have
several sponsors. The amount of financial support provided by each sponsor is recorded
for the event. Each sponsor is identified by a sponsor id. The name, contact email and
sponsor type are also recorded. A sponsor may support several events throughout the
year.
For some events such as career night, MCSS may also invite some guest speakers to
share their experience. The database records all guests’ information, the guests full
name, email and phone number are recorded. If a guest comes from an organisation or
an individual that provides a sponsorship to any of the MCSS events (does not have to
be at the event where the guest speaks), this fact will also be recorded. A guest may be
invited to several events.
Create a logical level diagram using Crow’s foot notations to represent the “Monash
Computing Students Society” data requirements described above. Clearly state any
assumptions you make when creating the model.
This model must be created using LucidChart (you MUST NOT use SQL Developer
Data Modeller). After you have built your model in LucidChart, export it as a png image
and add it to the answer paper via the MS Word Insert – Picture menu.
Please note the following points:
● Be sure to include all relations, attributes and relationships (unnecessary
relationships must not be included)
● Identify clearly the Primary Keys (P) and Foreign Keys (F), as part of your
design
● Surrogate keys must not be added
● In building your model you must conform to FIT9132 modelling requirements
● The following are NOT required on your diagram
● verbs/names on relationship lines
● indicators (*) to show if an attribute is required or not
● data types for the attributes
Page 4 of 13
Q3. Normalisation (10 marks)
The Super Electronics Invoice shown below displays the details of an invoice for the client
Alice Paul.
Super Electronics
INVOICE
Client Number: C3178713 Invoice No.: 132
Client Name: Alice Paul Invoice Date: 02/11/2018
Client Address: 43 High Street,
Caulfield, VIC 3162
Client Phone: 0411 245 718
ItemID Item Name Purchase
Price
Expected
Delivery Date
Quantity Cost
316772 Soniq S55UV16B 55″ 499.00 2 weeks 1 499.00
452550 Microsoft Surface Pro 1198.00 1-3 weeks 1 1198.00
483041 Delonghi Digital Coffee 299.00 Same Day 2 598.00
SUB TOTAL: $ 2295.00
DELIVERY: $145.00
ORDER TOTAL: $2440.00
Represent this form in UNF. In creating your representation you should note that Super
Electronics wish to treat the client name, address and phone as simple attributes.
Convert your UNF to first normal form (1NF) and then continue the normalisation to third
normal form (3NF). At each normal form show the appropriate dependencies for that normal
form, if there are none write “No Dependencies”
Do not add new attributes during the normalisation. Clearly write the relations in each
step from the unormalised form (UNF) to the third normal form (3NF). Clearly, indicate
primary keys on all relations from 1NF onwards.
[10 marks]
Page 5 of 13
Q4. SQL/NOSQL ( 6 + 10 + 10 + 4 + 4 + 6 + 10 = 50 marks)
A. SQL: 40 marks
The following relational model depicts an Employee System:
The schema file to create these tables is listed in Appendix A.
Given this model and assuming the tables have been created and populated in an Oracle
database, provide the SQL statements for the following requirements.
When coding SQL you must ensure each clause you use, such as SELECT, FROM, WHERE,
GROUP BY, HAVING, ORDER BY, CREATE, ALTER etc starts on a new line.
i. Display the course code, course name and duration for all those courses which are from the
course category “GEN” or “BLD”, order the output with the course with the longest duration first.
Where two courses have the same duration, order their output by the course code.
[6 marks]
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ii. For each department list the department name, the department location, the name of the
manager and the number of employees in that department. The name of the manager must be
output in a column called “MANAGERS NAME” and the number of employees must be output in a
column called “TOTAL EMPLOYEES”. Order the output by the number of employees in the
department.
[10 marks]
iii. List for all employees, the employee number, name, birthdate and the number of different
courses they have registered for. Note that some employees may repeat a course, this repeat does
not count as a different course. Order the output by employee number. Sample output will have the
form (only partial shown):
[10 marks]
iv. Add a new department to the DEPARTMENT table, this department’s number will be 10 higher
than the highest current department number and will be called EXAM and is located in BOSTON,
the department does not currently have a manager assigned. No sequences are available or may
be created.
[4 marks]
v. The employee named KING who has a job as the only company DIRECTOR has been assigned
to manage the new EXAM department. Record this in the database.
[4 marks]
vi. The company has decided that they wish to record, for each department, the number of
employees currently working in the department. Modify the database structure to allow this data to
be recorded. Initially, following your modification, the number of employees in each department
should be set to 0 – this will be updated at a later stage, you do not need to code this later update.
[6 marks]
Page 7 of 13
B. NOSQL: 10 marks
(i) Given this sample data:
and this select statement
SELECT
JSON_OBJECT( ‘_id’ VALUE empno,
‘name’ VALUE JSON_OBJECT(
‘initial’ VALUE empinit,
‘familyName’ VALUE empname
),
‘position’ VALUE empjob,
‘birthDate’ VALUE to_char(empbdate,’dd-mm-yyyy’),
‘courseInfo’ VALUE JSON_ARRAYAGG(
JSON_OBJECT(
‘code’ VALUE crscode,
‘date’ VALUE to_char(offbegindate,’dd-mm-yyyy’),
‘evaluation’ VALUE regevaluation
)
)
FORMAT JSON )
|| ‘,’
FROM PAYROLL.employee NATURAL JOIN payroll.registration
GROUP BY empno, empinit, empname, empjob,empbdate
ORDER BY empname;
Write the JSON formatted text for one of the employees listed in the table.
[4 marks]
(ii) Assume that the collection name is employees, write the MongoDB command to show all
employees who have a job as ‘MANAGER’
[2 marks]
(iii) Write the MongoDB command to show all employees who have a surname of ‘JONES’ or
‘SCOTT’
[4 marks]
Page 8 of 13
Q5. Transaction Management (5 + 5 = 10 marks)
a. Given two transactions:
T1 – R(X), W(X)
T2 – R(Y), W(Y), R(X), W (X)
Where R(X) means Read(X) and W(X) means Write(X).
i. If we wish to complete both of these transactions, explain the difference
between a serial and non-serial ordering of these two transactions.
Provide an example of each as part of your answer.
ii. What transaction ACID property does a non-serial ordering of these two
transactions potentially violate.
[5 marks]
b. A write through database has five transactions running as listed below (the time
is shown horizontally from left to right):
At time tc a checkpoint is taken, at time tf the database fails due to a power
outage.
Explain for each transaction what recovery operations will be needed when the
database is restarted and why.
[5 marks]
END OF EXAMINATION
Page 9 of 13
APPENDIX – Schema for Employee System
—
— Create Table : ‘SALGRADE’
— salgrade : Salary Grade
— sallower : Salary lower limit
— salupper : Salary upper limit
— salbonus : Salary bonus
—
CREATE TABLE SALGRADE (
salgrade NUMBER(2) NOT NULL ,
sallower NUMBER(6,2) NOT NULL ,
salupper NUMBER(6,2) NOT NULL ,
salbonus NUMBER(6,2) NOT NULL ,
CONSTRAINT salgrade_pk PRIMARY KEY (salgrade),
CONSTRAINT salgrade_chk1 CHECK (sallower >= 0),
CONSTRAINT salgrade_chk2 CHECK (sallower <= salupper));
COMMENT ON COLUMN salgrade.salgrade IS ‘Salary Grade’;
COMMENT ON COLUMN salgrade.sallower IS ‘Salary Lower Limit’;
COMMENT ON COLUMN salgrade.salupper IS ‘Salary Upper Limit’;
COMMENT ON COLUMN salgrade.salbonus IS ‘Salary Bonus’;
—
— Create Table : ‘COURSE’
— crscode : Course Code
— crsdesc : Course Description
— crscategory : Course Category
— crsduration : Course Duration
—
CREATE TABLE course (
crscode VARCHAR(6) NOT NULL ,
crsdesc VARCHAR(30) NOT NULL ,
crscategory CHAR(3) NOT NULL ,
crsduration NUMBER(2) NOT NULL ,
CONSTRAINT course_pk PRIMARY KEY (crscode),
CONSTRAINT course_chk1 CHECK (crscode = upper(crscode)),
CONSTRAINT course_chk2 CHECK (crscategory in (‘GEN’,’BLD’,’DSG’)));
COMMENT ON COLUMN course.crscode IS ‘Course Code’;
COMMENT ON COLUMN course.crsdesc IS ‘Course Description’;
COMMENT ON COLUMN course.crscategory IS ‘Course Category’;
COMMENT ON COLUMN course.crsduration IS ‘Course Duration’;
—
— Create Table : ‘DEPARTMENT’
— deptno : Department Number
— deptname : Department Name
— deptlocation : Location of department
— empno : Employee who manages department (references EMPLOYEE.empno)
— FK constraint cannot be added until employee table is created
—
CREATE TABLE DEPARTMENT (
deptno NUMBER(2) NOT NULL ,
deptname VARCHAR(10) NOT NULL ,
deptlocation VARCHAR(8) NOT NULL ,
empno NUMBER(4) ,
CONSTRAINT department_pk PRIMARY KEY (deptno),
CONSTRAINT department_un UNIQUE (deptname),
Page 10 of 13
CONSTRAINT department_chk1 CHECK (deptname = upper(deptname)),
CONSTRAINT department_chk2 CHECK (deptlocation = upper(deptlocation)));
COMMENT ON COLUMN department.deptno IS ‘Department Number’;
COMMENT ON COLUMN department.deptname IS ‘Department Name’;
COMMENT ON COLUMN department.deptlocation IS ‘Location of department’;
COMMENT ON COLUMN department.empno IS ‘Employee who manages department’;
—
— Create Table : ‘EMPLOYEE’
— empno : Employee number
— empname : Employee name
— empinit : Employee initials
— empjob : Employee job
— empbdate : Employee birthdate
— empmsal : Employee monthly salary
— empcomm : Employee commission
— deptno : Department Number (references DEPARTMENT.deptno)
— mgrno : Employees manager (empno of manager) (references EMPLOYEE.empno)
—
CREATE TABLE EMPLOYEE (
empno NUMBER(4) NOT NULL ,
empname VARCHAR(8) NOT NULL ,
empinit VARCHAR(5) NOT NULL ,
empjob VARCHAR(8) ,
empbdate DATE NOT NULL ,
empmsal NUMBER(6,2) NOT NULL ,
empcomm NUMBER(6,2) ,
deptno NUMBER(2) ,
mgrno NUMBER(4) ,
CONSTRAINT employee_pk PRIMARY KEY (empno),
CONSTRAINT employee_fk1 FOREIGN KEY (mgrno)
REFERENCES EMPLOYEE (empno),
CONSTRAINT employee_fk2 FOREIGN KEY (deptno)
REFERENCES DEPARTMENT (deptno));
COMMENT ON COLUMN employee.empno IS ‘Employee number’;
COMMENT ON COLUMN employee.empname IS ‘Employee name’;
COMMENT ON COLUMN employee.empinit IS ‘Employee initials’;
COMMENT ON COLUMN employee.empjob IS ‘Employee job’;
COMMENT ON COLUMN employee.empbdate IS ‘Employee birthdate’;
COMMENT ON COLUMN employee.empmsal IS ‘Employee monthly salary’;
COMMENT ON COLUMN employee.empcomm IS ‘Employee commission’;
COMMENT ON COLUMN employee.deptno IS ‘Department Number’;
COMMENT ON COLUMN employee.mgrno IS ‘Employees manager (empno of manager)’;
— Alter Table : ‘DEPARTMENT’
— empno : Employee who manages department (references EMPLOYEE.empno)
— Add constraint for Department table now employee exists:
ALTER TABLE DEPARTMENT
ADD (CONSTRAINT department_fk FOREIGN KEY (empno)
REFERENCES employee (empno));
Page 11 of 13
—
— Create Table : ‘HISTORY’
— deptno : Department Number (references DEPARTMENT.deptno)
— histbegindate : Date history record begins
— histbeginyear : Year history record begins
— histenddate : Date history record ends
— histmsal : Monthly Salary for this history record
— histcomments : Comments for this history record
— empno : Employee number (references EMPLOYEE.empno)
—
CREATE TABLE HISTORY (
empno NUMBER(4) NOT NULL ,
histbegindate DATE NOT NULL ,
histbeginyear NUMBER(4) NOT NULL ,
histenddate DATE ,
histmsal NUMBER(6,2) NOT NULL ,
histcomments VARCHAR(60) ,
deptno NUMBER(2) NOT NULL ,
CONSTRAINT history_pk PRIMARY KEY (empno, histbegindate),
CONSTRAINT history_chk CHECK (histbegindate < histenddate),
CONSTRAINT history_fk1 FOREIGN KEY (empno)
REFERENCES EMPLOYEE (empno)
ON DELETE CASCADE,
CONSTRAINT history_fk2 FOREIGN KEY (deptno)
REFERENCES DEPARTMENT (deptno));
COMMENT ON COLUMN history.deptno IS ‘Department Number’;
COMMENT ON COLUMN history.histbegindate IS ‘Date history record begins’;
COMMENT ON COLUMN history.histbeginyear IS ‘Year history record begins’;
COMMENT ON COLUMN history.histenddate IS ‘Date history record ends’;
COMMENT ON COLUMN history.histmsal IS ‘Monthly Salary for this history record’;
COMMENT ON COLUMN history.histcomments IS ‘Comments for this history record’;
COMMENT ON COLUMN history.empno IS ‘Employee number’;
—
— Create Table : ‘OFFERING’
— offbegindate : Begin date for offering
— crscode : Course Code (references COURSE.crscode)
— offlocation : Location for offering
— empno : Employee number for employee running offering (references
EMPLOYEE.empno)
—
CREATE TABLE OFFERING (
offbegindate DATE NOT NULL ,
crscode VARCHAR(6) NOT NULL ,
offlocation VARCHAR(8) ,
empno NUMBER(4) ,
CONSTRAINT offering_pk PRIMARY KEY (offbegindate, crscode),
CONSTRAINT offering_fk1 FOREIGN KEY (crscode)
REFERENCES course(crscode),
CONSTRAINT offering_fk2 FOREIGN KEY (empno)
REFERENCES EMPLOYEE (empno));
COMMENT ON COLUMN offering.offbegindate IS ‘Begin date for offering’;
COMMENT ON COLUMN offering.crscode IS ‘Course Code’;
COMMENT ON COLUMN offering.offlocation IS ‘Location for offering’;
COMMENT ON COLUMN offering.empno IS ‘Employee number for employee running
offering’;
—
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— Create Table : ‘REGISTRATION’
— offbegindate : Begin date for offering (references OFFERING.offbegindate)
— crscode : Course Code (references OFFERING.crscode)
— regevaluation : Grade for course completed
— empno : Employee number of employee completing course (references
EMPLOYEE.empno)
—
CREATE TABLE REGISTRATION (
offbegindate DATE NOT NULL ,
crscode VARCHAR(6) NOT NULL ,
empno NUMBER(4) NOT NULL,
regevaluation NUMBER(1) ,
CONSTRAINT registration_pk PRIMARY KEY (offbegindate, crscode, empno),
CONSTRAINT resgitration_chk CHECK (regevaluation in (1,2,3,4,5)),
CONSTRAINT registration_fk1 FOREIGN KEY (empno)
REFERENCES EMPLOYEE (empno),
CONSTRAINT registration_fk2 FOREIGN KEY (offbegindate, crscode)
REFERENCES OFFERING (offbegindate, crscode));
COMMENT ON COLUMN registration.offbegindate IS ‘Begin date for offering’;
COMMENT ON COLUMN registration.crscode IS ‘Course Code’;
COMMENT ON COLUMN registration.regevaluation IS ‘Grade for course completed’;
COMMENT ON COLUMN registration.empno IS ‘Employee number of employee completing
course’;