Java代写 | Programming Assignment | CS代写 | Java NetBeans

Java代写/Java Basic/Java 数据处理/Java IO/Java Math/Introduction to Programming/NetBeans

该门课程为暑校的编程入门课,本次作业使用Java读取CSV学生成绩数据,并对数据进行平均分、最高分、最低分等数学统计

Notice to Students

  1. This assignment should be written by individual student. All downloaded materials are not allowed.
  2. Plagiarism will be treated seriously. All assignments that have been found involved wholly or partly in plagiarism (no matter these assignments are from the original authors or from the plagiarists) will score ZERO marks.
  3. Your program should use Java JDK8 or above and NetBeans to develop.
  4. Your program must be structured and well commented.

The first few lines in the source file must be comments stating the name of the source file, student name, student ID, course name, course code, and brief description of your program.

/********************************************************

Name of Source File:  xxxxx.java

Student Name (ID): Chan Tai Man (141414141)

Course Name (Code):   HD in MAD (IT114112)

Program Description:

This program is . . . . . . .

. . . . .

. . . . .

********************************************************/

 

Marks will be deducted if such comments are not included.

  1. You are required to hand a zip file containing the NetBeans project
  2. Weight of this assignment is 20% of the module total assessment.

Generating a Student Report

Background

A final mark of a student consists of four sub marks: CA lab mark, CA test mark, EA

assignment mark, and EA test mark.

The following formula is used to calculate a student’s final mark:

Final_Mark = CA_Test_Mark x 0.2 + CA_Lab_Mark x 0.3 + EA_Test_Mark x 0.3  + EA_Assignemt_Mark x 0.2

To determine if a student passes, the student need to achieve an attendance of at least 70% and a final mark of 40%.

Requirements

Given a text file “StudentsData.csv” of student data sample with 6 columns of data, write a Java program that reads the file, check if each line of record has all the column data, calculates the final mark of each student, and output the average, highest, and lowest marks of the students. The program will also indicate the reason of failing (either attendance <70% or final mark <40%). Assume there are no more than 50 students in a class.

Below is the supplied sample data in “StudentsData.csv”:

Wong Ka Lung;39;77.9;88;80.1;92.3

Lee Chun Sing;35.7;80.5;91.8;85;85.5

Cheung Chi Ling;33.4;76.2;75;70;66.2

Lau Mei Yan;36.8;50;65.3;62.4;71.1

Chan Fong Wa;39;64.7;82.6;60;80.9

Yeung Kwok Sun;39;46.8;60;55.2;74.6

Kwok Siu Fong;26;60.3;72.5;65.6;80

Chiu Wai Hung;29;46.4;37.1;20.7;53.4

Ng Ka Kei;34.7;35;66.3;;61.3

Chau Wai Chun;39;66.8;74.7;72.8;77.8

 

Tasks

  1. Write appropriate methods to do the following tasks, one method for each:

–        Read the “StudentsData.csv” file and check if each line has filled in all the column before assigning them in to five different arrays. Output message if information is missing.

–        Calculate the final marks, average mark, highest mark, and lowest mark of the students.

  • Display result according to the sample output.
  1. “StudentsData.csv” consists of 6 columns of data. The delimiter “;” is used.

-The first column is student’s name.

-The second column is the attendance hours of the student. (Max 39 hours)

-The third column is the CA test mark of the student.

-The forth column is the CA lab mark of the student.

-The fifth column is the EA test mark of the student.

-The sixth column is the EA assignment mark of the student.

 

For example, the first line of “StudentsData.csv”:

Wong Ka Lung;39;77.9;88;80.1;92.3

Student name = Wong Ka Lung

Attendance = 39

CA test mark = 77.9

CA lab mark = 88

EA test mark = 80.1

EA assignment mark = 92.3

Assessment scheme

 

–        Problem solving technique, e.g. algorithms                                              (15 marks)

–        Java programming technique, e.g. statements, control structures, etc.     (15 marks)

–        Programming style, e.g. naming, comments, etc.                                     (10 marks)

 


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